Question 536002
Given to solve for x:
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{{{3x/5-2/6 =20}}}
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Clear the fractions by multiplying all terms on both sides by (5*6) as follows:
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{{{(5*6*3x)/5 - (5*6*2)/6 = 5*6*20}}}
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cancel the denominators with the same value in the corresponding numerator:
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{{{(cross(5)*6*3x)/cross(5) - (5*cross(6)*2)/cross(6) = 5*6*20}}}
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as a result of this procedure the equation becomes:
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{{{6*3x - 5*2 = 5*6*20}}}
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do the multiplications in each term and the result is:
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{{{18x - 10 = 600}}}
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get rid of the -10 on the left side by adding 10 to both sides. On the left side of the equation the -10 and the +10 cancel each other. On the right side this just adds 10 to 600. The equation is then:
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{{{18x = 610}}}
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Solve for x by dividing both sides by 18. The result is:
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{{{x = 610/18}}}
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Do the division of 18 into 610 and you get the answer:
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{{{x = 33.8888889}}}
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Hope this helps you to understand one way of clearing the fractions in an equation so that you can work the problem using integers.
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