Question 535976
The ladder,the floor & the wall form a right triangle.													
The base is one leg					The height is the other leg								
The ladder acts as the hypotenuse													
Pythagoras theorem													
													
(Hyp)^2= 		(leg1)^2+			Leg2^2								
Hypotenuse =			9	ft									
leg1=			2	ft									
Leg2=			?										
													
leg2^2=hyp^2-leg1^2													
Leg2^2= 9^2-2^2							
Leg2^2= 81-4									
Leg2^2=77											
Leg2= {{{sqrt(175)}}}											
Leg2=	8.77	ft  --- The height it reaches


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The sides and the diagonal form a right triangle									
The length is one leg & the width is the other leg									
One leg				450	m				
Second leg				250	m				
Hypotenuse 				x 	m				
By Pythagoras theorem 									
Hypotenuse^2 = Leg1^2+leg2^2									
{{{ 	x 	^2	=	450	^2	+	250	^2}}}	
x 	^2	=	202500	+	62500				
x 	^2	=	265000						
{{{ sqrt(x^2)=		sqrt(	265000	)}}}					
x=	514.78	m							
									
The sum of the sides =					700	m			
The diagonal =					514.78	m			
									
The difference=					185.22	m			
									
185.22	m	will be saved	

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The rope forms the hypotenuse of the right triangle 
One leg				250	cm				
Second leg				120	cm				
Hypotenuse 				x 	cm				
By Pythagoras theorem 									
Hypotenuse^2 = Leg1^2+leg2^2									
{{{ 	x 	^2	=	250	^2	+	120	^2}}}	
x 	^2	=	62500	+	14400				
x 	^2	=	76900						
{{{ sqrt(x^2)=		sqrt(	76900	)}}}					
x=	277.31	cm  the length of the rope.

There are 3 ropes . multiply by 3  to get the total length required		

						
									
m.ananth@hotmail.ca