<PRE><B>Question 535888</B>
If computer a can process 10 pictures in 180 sec, and working together with computer b, processes them in 100 sec,
 how long does it take for b to process the same amount of pictures
:
let b = time required by b alone
let the completed job = 1 (10 pics processed)
:
A typical shared work equation
{{{100/180}}} + {{{100/b}}} = 1
mult by 180b 
180b*{{{100/180}}} + 180b*{{{100/b}}} = 180b
Cancel the denominators and you have
100b + 180(100) = 180b
18000 = 180b - 100b
18000 = 80b
b = {{{18000/80}}}
b = 225 sec alone </PRE>