Question 535794
Solve:
1) {{{(x+4)/(x-3) = (x+10)/(x+2)}}} Cross-multiply.
{{{(x+4)(x+2) = (x+10)(x-3)}}} Perform the indicated multiplication.
{{{x^2+6x+8 = x^2+7x-30}}} Subtract {{{x^2}}} from both sides.
{{{6x+8 = 7x-30}}} Subtract 6x from both sides.
{{{8 = x-30}}} Add 30 to both sides.
{{{38 = x}}}  or {{{highlight(x = 38)}}}
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2) {{{5/(3x)+3/x = 1}}} Use the common denominator of 3x to add the two fractions.
{{{5/(3x)+3*3/3x = 1}}}
{{{(5+9)/3x = 1}}} Multiply boh sides by 3x.
{{{14 = 3x}}} Divide both sides by 3.
{{{14/3 = x}}} or {{{x = 4}}}{{{2/3}}}