<PRE><B>Question 535794</B>
{{{((x+4))/((x-3))}}} = {{{((x+10))/((x+2))}}}
Cross multiply
(x+4)(x+2) = (x-3)(x+10)
FOIL
x^2 + 2x + 4x + 8 = x^2 + 10x - 3x - 30
x^2 + 6x + 8 = x^2 + 7x - 30
Combine the x&#39;s on the left, combine the numbers on the right
x^2 - x^2 + 6x - 7x = -30 - 8
-x = -38
which is
x = 38
Check this in the original problem
:
 {{{5/(3x)}}} + {{{3/x}}} = 1
Multiply by 3x
3x*{{{5/(3x)}}} + 3x*{{{3/x}}} = 3x(1)
Cancel the denominators, and you have:
5 + 3(3) = 3x
14 = 3x 
x = 14/3
x = 4{{{2/3}}}
:
:
Check this in the original, you can use 4.67 to do this on a calc, it should be very close to 1</PRE>