Question 535736
You want to simplify {{{(7x^3+3x^2)(2x-3)/(2xy-3y)(7xy^6+3y^6)}}}
You'll need to do some factoring. Do you see any common factor that could evenly divide {{{7x^3}}} and {{{3x^2}}}?
How about {{{2xy}}} and {{{3y}}}?
How about {{{7xy^6}}} and {{{3y^6}}}?
If you see some common factors you could try factoring and then simplifying like this
{{{(7x^3+3x^2)(2x-3)/(2xy-3y)(7xy^6+3y^6)=x^2(7x+3)(2x-3)/(y*(2x-3)y^6(7x+3))=(x^2/y^7)((2x-3)/(2x-3))((7x+3)/(7x+3))=x^2/y^7}}}