Question 535785
y=-2x^2+6 How do I graph this?
This is an equation of the standard form for a parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
For given equation: 
vertex:(0,6)
negative lead coefficient means parabola opens downwards
y-intercept
set x=0
y=6
..
x-intercepts:
set y=0
2x^2=6
x^2=3
x=±√3
..
you now have the vertex(0,6), y-intercept(0,6) and two x-intercepts(±√3,0)
with which you can easily draw the graph of given function.