<PRE><B>Question 1186</B>
 Let Vo be the initial vertical velocity of the ball.
 
 Since h = vot - 1/2 gt^2, 
 and we know h = 24 m when t = 2 sec, we have
 24 = 2 Vo - 2*9.8 ,
 2 Vo = 24 + 19.6 = 43.6,
 So Vo = 21.8 m/s
 
 By the formula V^2 = Vo^2 - 2g h and so h is maximum when V =0,
 so h(max) = Vo^2 / 2g = (21.8)^2 / 19.6 = 24.25 meters

 Answwer: Maximum height is 24.25 meters
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