Question 535704
Factor:
{{{t^5-29t^3+100t}}} First factor a t.
{{{t(t^4-29t^2+100)}}} Now you can rewrite the trinomial interms of {{{t^2}}} thus:
{{{t((t^2)^2-29(t^2)+100)}}} Now factor the re-written trinomial.
{{{t(t^2-4)(t^2-25)}}} Now you factor the two "difference of squares" factors, recalling that:{{{A^2-B^2 = (A+B)(A-B)}}}.
{{{highlight(t(t+2)(t-2)(t+5)(t-5))}}}