Question 535537
A stadium has 49000 seats. 
Seats sell for $25 in Section A, z
$20 in Section B,-------------------x seats
$15 in Section C. ------------------y seats

(x+y)=z

25(x+y)+20x+15y=1052000
25x+25y+20x+15y=1052000
45x+40y=1052000
/5
9x+8y=210400------------------1
2x+2y=49000
/2
x+y=24500
multiply by -9
-9x-9y=-220500----------------2

add equation (1) & (2)
-y=-10100
y= 10100  Section C
plug value of y in equation x+y = 24500
x+10100=24500
x=14400 seats Section B

x+y = Z= 24500 Section A

CHECK

24500+14400+10100= 49,000

24500*25+14400*20+15*10100=1,052,000

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