Question 535479
{{{(z/4-5)^2/3 = 1/25}}}
I would change {{{ 1/25}}} to {{{ (1/5)^2 }}}
{{{(z/4-5)^2/3 = (1/5)^2}}}
Then I would change {{{ 1/3}}} to {{{ 1/(sqrt(3))^2 }}}
Now I have
{{{ ( (z/4-5)/sqrt(3) )^2 = (1/5)^2}}}
Take the square root of both sides
{{{  (z/4-5)/sqrt(3)  = 1/5}}}
{{{ z/4 - 5 = sqrt(3)/5 }}}
{{{ z/4 = sqrt(3)/5 + 5 }}}
{{{ z = (4/5)*sqrt(3) + 20 }}}
check answer:
{{{ z/4 = (1/5)*sqrt(3) + 5 }}}
{{{ z/4 - 5 = (1/5)*sqrt(3) }}}
{{{ ( z/4 - 5 )^2 = 3/25 }}}
{{{ (( z/4 - 5 )^2)/3 = 1/25 }}}
OK