Question 535318


to find the perimeter of rectangle with coordinates A (-3, 4), B (-3, 7), C (10, 4) and D (10, 7), first find the length of sides

A (-3, 4), B (-3, 7)....both have same {{{x}}} and the length of side {{{AB=7-4=3}}}

 C (10, 4) and D (10, 7),...both have same {{{x}}} and the length of side {{{CD=7-4=3}}}

A (-3, 4), C (10, 4)...both have same {{{y}}} and the length of side {{{AC=10-(-3)=10+3=13}}}

B (-3, 7), D (10, 7)...both have same {{{y}}} and the length of side {{{BD=10-(-3)=10+3=13}}}

so, {{{a=3}}} and {{{b=13}}} and the perimeter of rectangle is {{{P=2(a+b)=2(3+13)=2*16=32}}}