Question 535317
"if 83% of seeds will sprout and 10 are selected at random, what is the probability that at least 8 will sprout" 
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Binomial Problem with n = 10 and p(sprout) = 0.83
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P(8<= x <=10) = 1 - binomcdf(10,0.83,7) = 0.7659
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Cheers,
Stan H.
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