<PRE><B>Question 535246</B>
&lt;B&gt;Check my profile and contact me for one on one online tutoring.&lt;/B&gt;&lt;P&gt;

Point slope form is y-y1 = m (x-x1):  Keep in mind y1 and x1 mean y sub 1 and x sub 1, the y and x-coordinate for the point you&#39;ll use.&lt;P&gt;

x1 = -3 and y1=4 and m 7/2&lt;P&gt;

y-4=(7/2)(x+3)  (x-(-3) = x+3).&lt;P&gt;

For the second problem remember the slope-intercept equation is y=mx+b where m is the slope and b is the y-intercept (y when x=0).&lt;P&gt;

We need a slope, and one point to find the equation.  We&#39;ll use one point and the slope to find the b value.  First we have to find the slope which is&lt;P&gt;
Difference in y divided by difference in x&lt;P&gt;
(y-y1) / (x-x1)  It doesn&#39;t matter which point we choose as (x,y) and which as (x1,y1).&lt;P&gt;

We&#39;ll use (-2,0) as (x,y) and (0,3) as (x1,y1)&lt;P&gt;

slope=m=(0-3)/(-2-0) = -3/-2 = 3/2.&lt;P&gt;

Plug that slope and the values for either point into y=mx+b to find b.  We&#39;ll use (-2,0)&lt;P&gt;

0=(3/2)(-2)+b  ---&gt;  0 = -3 + b (add 3 to both sides)  3=b.&lt;P&gt;

We have b=3 and m = 3/2, so the slope-intercept equation y=mx+b is:&lt;P&gt;
y = (3/2)x + 3</PRE>