Question 534886
{{{ x^3+3x^2-4x=0 }}}
{{{ x*( x^2 + 3x - 4 ) = 0 }}}
{{{ x*( x - 1 )*( x + 4 ) = 0 }}}
the solutions are
{{{ x = 0 }}}
{{{ x = 1 }}}
{{{ x = -4 }}}
check:
{{{ x^3+3x^2-4x=0 }}}
{{{ (-4)^3 + 3*(-4)^2-4*(-4) = 0 }}}
{{{ -64 + 48 + 16 = 0 }}}
{{{ -64 + 64 = 0 }}}
OK