Question 534751
Find the equation for the tangent line to the curve y= f(x) where through the point (1, -3) where f(x)= x^8- 4x
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f'(x) = 8x^7 - 4
f'(1) = 4 = slope
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-3 = 4*1 + b
b = -7
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y = 4x - 7