Question 534544
={{{((7v-28)/121)/((v-4)/55v)}}}
={{{((7v-28)/121)*(55v/(v-4))}}}
={{{(7(v-4)/cross(121))*(cross(55)v/(v-4))}}}
={{{(7(v-4)/11)*(5v/(v-4))}}}
={{{((7)cross((v-4))/11)*(5v/cross(v-4))}}}
={{{(7/11)*(5v)}}}
={{{35v/11}}}
={{{(3&2/11)(v)}}}