Question 534464
Given equation can be written as
 2x^3-x^2-15x=0.

i.e.,  x[2x^2-x-15]=0
 
       x=0, 2x^2-x-15=0 
             
   To solve this quadratic equation we follow the steps
  1) multiply the coefficient of x^2 and constant term = -30
  2) Now we split -30 as product of two numbers and if we add that two numbers we get the coefficient of x.
       i.e., -30 = (-6)x(5)      
  3) 2x^2-6x+5x-15=0  ==> 2x(x-3)+5(x-3)=0
  4) 2x+5=0, x-3=0
  5) x=-5/2, x=3

  Finally we get the roots of x are  x=0,3,-5/2