Question 534417
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It depends on whether the order in which they are answered is important or not, i.e. is answering 1,2,3,4,5,6,7,8,9 the same or different from 2,1,3,4,5,6,7,8,9?


If the two results above are different, then you need *[tex \Large _9P_{14}\ =\ \frac{14!}{(14-9)!]


If the two results above are the same, then you need *[tex \Large _9C_{14}\ =\ \frac{14!}{9!(14-9)!]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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