Question 534399
f(x) = 1/4(x+2)^2 +4
f(x) = 1/4(x^2 +4x + 4) + 4
f(x) = 1/4*x^2 +x + 5
.
axis of symmetry = -b/2a
-b/2a = -1/(2*1/4) = -1/(1/2) = -2
vertex = 1/4(-2+2)^2 +4 = 4
(-2,4)
.
{{{ graph(500,500,-10,10,-10,10,1/4*(x+2)^2+4) }}}