Question 534370
Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form of y=mx+b 
(2,-6); 8x + 5y = 6 
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Find the slope of the line.
To do that, put it in slope-intercept form.  That means solve for y.
8x + 5y = 6
5y = -8x + 6
y = (-8/5)x + 6/5
The slope, m, is the coefficient of x in this form.
m = -8/5
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The slope of lines perpendicular is the negative inverse.
m = 5/8
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Use y = mx + b and the point (2,-6) to find b
-6 = (5/8)*2 + b
b = -29/4
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For the line perpendicular, m = 5/8 and b = -29/4
--> y = (5/8)x - 29/4