Question 534112
With 2 dice there are 36 possible outcomes:  6*6 =36.
The following table shows the possible sums of 2 dice.
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<TABLE border="3">
<tr><th><th colspan="7">Die 1</tr>
<tr><th rowspan="8">Die 2</tr>
<tr><th>&nbsp;&nbsp;&nbsp;<th>1&nbsp;&nbsp;&nbsp;<th>2&nbsp;&nbsp;&nbsp;<th>3&nbsp;&nbsp;&nbsp;<th>4&nbsp;&nbsp;&nbsp;<th>5&nbsp;&nbsp;&nbsp;<th>6&nbsp;&nbsp;&nbsp;</tr>
<tr><th>1&nbsp;&nbsp;&nbsp;<td>2<td>3<td>4<td>5<td>6<td>7</tr>
<tr><th>2&nbsp;&nbsp;&nbsp;<td>3<td>4<td>5<td>6<td>7<td>8</tr>
<tr><th>3&nbsp;&nbsp;&nbsp;<td>4<td>5<td>6<td>7<td>8<td>9</tr>
<tr><th>4&nbsp;&nbsp;&nbsp;<td>5<td>6<td>7<td>8<td>9<td>10</tr>
<tr><th>5&nbsp;&nbsp;&nbsp;<td>6<td>7<td>8<td>9<td>10<td>11</tr>
<tr><th>6&nbsp;&nbsp;&nbsp;<td>7<td>8<td>9<td>10<td>11<td>12</tr>
</table>

The question is what is the probability the sum is at least 10.
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1 of these 36 outcomes = 12
2 of these 36 outcomes = 11
3 of these 36 outcomes = 10 
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P(10 or more) = 6/36 = 1/6
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Done