Question 533834
Solve for x
7^(x-3)=4^(2x+1)
(x-3)log7=(2x+1) log4
(x-3)/(2x+1)=log4/log7≈.7124
x-3=(.7124)(2x+1)=1.4248x+.7124
.4248x=-3.7124
x=-3.7124/.4248
x=-8.7392