Question 534055
write an equation for the conic section.
parabola with vertex at (0,0) and focus at (0,3)
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Standard form of equation for given parabola: (x-h)^2=4p(y-k), with (h,k) being the (x,y) coordinates of the vertex. Parabola opens upwards.
vertex: (0,0) (given)
Axis of symmetry: x=0 or y-axis
p=3 (distance from vertex to focus on the axis of symmetry)
4p=12
Equation for given parabola:
x^2=12y