Question 534076
Sum of the areas of 2 squares is 468 m squared. If the difference of their perimeters is 24m, find the sides of the 2 squares.
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{{{s1^2 + s2^2 = 468}}} Areas
4s1 - 4s2 = 24 Perimeters, s1 is larger
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s1 - s2 = 6
s1 = s2 + 6
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{{{s1^2 + s2^2 = 468}}}
{{{(s2+6)^2 + s2^2 = 468}}}
{{{s2^2 + 12s + 36 + s2^2 = 468}}}
{{{2s2^2 + 12s + 36 = 468}}}
{{{s2^2 + 6s - 216 = 0}}}
(s - 12)*(s + 18) = 0
Sides are 12 & 18 meters