Question 533771
Solve the equation below. Please show all of your work.
log2(1/64)=1/3-x
log2(1/(2^6))=1/3-x
log2(2^-6)=1/3-x
log of base to a power=power 
-6=1/3-x
x=1/3+6=1/3+18/3=19/3
x=19/3