Question 533905
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That is because you are guessing and you are trying to make this too difficult.  Let *[tex \Large x] represent the number of standard version downloads, just like you did.  Then the number of megabytes downloaded for standard version downloads was *[tex \Large 2.6x], just like you have it.  But then you chose to add the variable *[tex \Large y] into the mix.  That's ok, in and of itself, but why did you multiply *[tex \Large y] by 4?


You were given that the high quality downloads outnumbered the standard downloads by a factor of 4.  So if you insist on having a *[tex \Large y] variable to represent the high-quality download quantity, then you can always say that *[tex \Large y\ =\ 4x]


What you have going on in parentheses after the *[tex \Large 4y] makes no sense.  You are putting in still <i><b>another</b></i> factor of 4!?


Let's recap:  *[tex \Large x] is the number of standard downloads, and *[tex \Large 2.6x] is the total size of the standard downloads.  *[tex \Large y] is the number of high quality downloads, and *[tex \Large 4.4y] is the total size of the high quality downloads.  We know that the sum of these two sizes is 4444 megabytes, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2.6x\ +\ 4.4y\ =\ 4444]


But we know that *[tex \Large y\ =\ 4x], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2.6x\ +\ 4.4(4x)\ =\ 4444]


Solve for *[tex \Large x]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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