Question 533773
percent		----------------			quantity								
Alcohol I	15	----------------			x	ml							
Alcohol II	45	------	300	-	x	ml							
Mixture	25.00%	----------------	300										
													
15x+45(300-x)=25*300	
													
15x+13500-45x	=7500			
15	x	-	45	x=	7500	-	13500			
-30	x=	-6000								
/	-30												
x	=200	ml			15.00%		Alcohol I	
100		ml			45.00%		Alcohol II