Question 533554
Solve for x?
{{{Log[4](x^2-3)+Log[4](10) = 1}}} Apply the product rule for logarithms:{{{Log[b](x)+Log[b](y) = Log[b](x*y)}}}
{{{Log[4]((x^2-3)(10)) = 1}}} Simplify.
{{{Log[4](10x^2-30) = 1}}} Rewite in exponential form:
{{{4^1 = 10x^2-30}}} Add 30 to both sides.
{{{34 = 10x^2}}} Divide by 10.
{{{3.4 = x^2}}} Take the square root of both sides.
{{{sqrt(3.4) = x}}} So...
{{{x = sqrt(3.4)}}} or {{{x = -sqrt(3.4)}}}