Question 533268
I try to think of numbers that are
around 1945 when you square them. 
{{{ 50*50 = 2500 }}} too high
{{{ 40*40 = 1600 }}} too low
{{{ 45*45 = 2025 }}} too high
{{{ 44*44 = 1936 }}} just right
That would make Bruce 9 years old
( depending on the month he was born )
In 1988 on his birthday, Bruce would
be exactly {{{ 1988 - 1936 = 52 }}}
52 years old
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Let {{{ c }}} = number of cows
Let {{{ t }}} = number of turkeys
Number of heads = {{{ c + t }}}
Number of legs = {{{ 4c + 2t }}}
given:
{{{ c + t = 4c + 2t - 35 }}}
This is 1 equation with 2 unknowns, so it
isn't directly solvable, but I can make guesses
Subtract {{{c}}} from both sides
{{{ t = 3c + 2t - 35 }}}
Subtract {{{t}}} from both sides
{{{ 0 = 3c + t - 35 }}}
Add {{{5}}} to both sides
{{{ 3c + t = 35 }}}
What if there are 10 cows?
{{{ 3*10 + t = 35 }}}
{{{ t = 35 - 30 }}}
{{{ t = 5 }}}
What if there are 11 cows?
{{{ 3*11 + t = 35 }}}
{{{ t = 35 - 33 }}}
{{{ t = 2 }}}
What if there are 12 cows?
{{{ 3*12 + t = 35 }}}
{{{ t = 35 - 36 }}}
There can't be minus one turkey, so
the largest possible number of cows
is 11
check answer:
{{{ c + t = 4c + 2t - 35 }}}
{{{ 11 + t = 4*11 + 2t - 35 }}}
{{{ 11 + t = 9 + 2t }}}
Subtract {{{9}}} from both sides
{{{ 2 + t = 2t }}}
Subtract {{{t}}} from both sides
{{{ t = 2 }}}
That's correct