Question 532891
a(a+2)=8
{{{a^2}}}+2a=8
{{{a^2+2a+1^2}}}={{{8+1^2}}} ---Completing the square.
{{{a^2+2a+1^2}}}={{{8+1}}}
{{{(a+1)^2}}}=9
{{{sqrt((a+1)^2)}}}={{{sqrt(9)}}}
a+1=+3/-3 (was not able to enter +- symbol) 


a=-4 OR a=2