Question 52566
When you have straight bars around that value, it is called absolute value.
It, in easier mathematical terms, is described by: {{{sqrt((x + 6)^2)}}}
That means that every value plugged for {{{x}}} gives you a positive number or zero.
Lets do an example:
|x + 1| = 2
{{{sqrt((x + 1)^2) = 2}}}
{{{(x + 1)^2 = 4}}}
{{{x + 1 = 2}}} and {{{x + 1 = -2}}}
{{{x = 1}}} and {{{x = -3}}}
{{{graph(300,300,-5,5,-5,5,sqrt((x+1)^2),2)}}}
Now, lets do your problem:
|x + 6| + 8 = 4
|x + 6| = -4 Remember, I said that absolute values gives you positive values or zero. There is no way it will give you negative four, so there are no solutions.
{{{graph(300,300,-8,2,-5,5,sqrt((x+6)^2),-4)}}}