<PRE><B>Question 532665</B>
Approximately 8% of people are left-handed. If two people are selected at random, what is the probability of the following events? 
A. P(Both are right-handed) = (0.92)^2
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B. P(Both are left-handed) = (0.08)^2
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C. P(One is right-handed and the other is left-handed) = 1 -[0.92^2+0.08^2]
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D. P(At least one is right-handed) = 1 - 0.08^2
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Cheers,
Stan H. 
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