<PRE><B>Question 532306</B>
An investor has a total $18,000 deposited in three different accounts, which earn annual interest of 9%, 7%, and 5%. The account deposited in the 9% account is twice the amount in the 5% account. If the three accounts earn total annual interest of $1340, how much money is deposited in each account?
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Quantity Eq:: n + s + f = 18000
Quantiy Eq: n = 2f
Interest Eq: 9n+7s+5f = 134000
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 n + s + f  = 18000
 n + 0 - 2f = 0
9n +7s + 5f = 134000
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Use any method you know to find:
n = 9% investment = $8000 
s = 7% investment = $6000
f = 5% investment = $4000
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Cheers,
Stan H.
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