Question 532299
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Just take the definition of *[tex \Large g(x)] and insert it in place of *[tex \Large x] in the definition of *[tex \Large f(x)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (f\,\circ\,g)(x)\ =\ f\left(g(x)\right)\ =\ -6\left(g(x)\right)\ +\ 5\ =\ -6\left(x^2\ +\ 8x\right)\ +\ 5]


All that is left is to simplify.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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