Question 52506
You can not divide by zero.
This can not be: x^2 + x = 0
x(x + 1) = 0
x = 0 and x = -1
Those are your vertical asymptotes.
There are infinite linear asymptotes. Ex.) y = x + 2
There are no horizontal asymptotes.
{{{graph(300,300,-10,10,-10,10,x+2,(x^3-1)/(x^2+x))}}}