Question 531652
{{{ (x-2)^5 = (x-2)*(x-2)^2*(x-2)^2 }}}
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{{{ (x-2)^2 = x^2-4*x+4 }}}
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{{{ (x-2)*(x^2-4*x+4) = x^3-6*x^2+12*x-8 }}}
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{{{ (x^3-6*x^2+12*x-8)*(x^2-4*x+4) = x^5-10*x^4+40*x^3-80*x^2+80*x-32 }}}
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{{{ (x-2)^5 = x^5-10*x^4+40*x^3-80*x^2+80*x-32 }}}
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Done.