Question 531612
The Sum of the squares of two consecutive odd integers is 74. Find the integers. 
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1st odd: 2x-1
2nd odd: 2x+1
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Equation:
(2x-1)^2 + (2x+1)^2 = 74
4x^2-4x+1 + 4x^2+4x+1 = 74
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8x^2+2 = 74
8x^2 = 72
x^2 = 9
x = 3 or x = -3
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If x = 3,
1st: 2x-1 = 5
2nd: 2x+1 = 7
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If x = -3,
1st: 2x-1 = -7
2nd: 2x+1 = -5
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Cheers,
Stan H.
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