Question 531547
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -11\ -\ 5a\ =\ 6(5a\ +\ 4)]


Distribute the 6 in the RHS


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -11\ -\ 5a\ =\ 30a\ +\ 24]


Add 11 to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -5a\ =\ 30a\ +\ 35]


Add *[tex \Large -30a] to both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -35a\ =\ 35]


Multiply both sides by *[tex \Large -\frac{1}{35}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ -1]


Check:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -11\ -\ \left(5(-1)\right)\ =^?\ 6\left(5(-1)\ +\ 4\right)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -6\ =^?\ -30\ +\ 24]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -6\ =\ -6]


Checks.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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