Question 531365
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There are only 4 possibilities.  Circles, ellipses, and hyperbolas all have both *[tex \Large x^2] and *[tex \Large y^2] terms.  This equation only has an *[tex \Large x^2] term.  Hence the curve must be a...


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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