Question 531212
 2(2x+5/3x)^2 -5 = 9(2x+5/3x) 
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Let w = (2x+5)/(3x)
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2w^2 - 9w -5 = 0
2w^2-10w+w-5 = 0
2w(w-5)+(w-5) = 0
(w-5)(2w+1) = 0
w = 5 or w = -1/2
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solve for "x":
If w = 5 you get:
(2x+5)/(3x) = 5
2x+5 = 15x
13x = 5
x = 5/13
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If x = -1/2 you get:
(2x+5)/(3x) = -1/2
4x+10 = -3x
7x = -10
x = -10/7
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cheers,
Stan H.
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