Question 531060
A Chemist has a mixture that is 10% iodine and another that is 50% iodine. How much of each solution should the druggist use to get 100 ml of a solution that is 20% iodine
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Equation:
active + active = active
0.10x + 0.50(100-x) = 0.20*100
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Multiply thru by 100 to get:
10x + 50*100 - 50x = 20*100
-40x = -30*100
x = 75 ml (amt. of 20% solution needed)
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100-x = 25 ml (amt. of 50% solution)
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Cheers,
Stan H.
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