Question 530882
A number exceeds four times its reciprocal by 3. Find the number. 


Let the number be N


Based on the given info., we can say that: {{{N = 4(1/N) + 3}}}


{{{N^2 = 4 + 3N}}} ------ Multiplying by LCD, N


{{{N^2 - 3N - 4 = 0}}}


(N - 4)(N + 1) = 0


N, or number = {{{highlight_green(4)}}} or {{{highlight_green(- 1)}}}


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