Question 530668
{{{(6-i)/(5+4i)}}} Multiply both the numerator and the denominator by the complex conjugate of {{{(5+4i)}}} which is {{{(5-4i)}}}.
{{{(6-i)(5-4i)/(5+4i)(5-4i)}}} Multiply using FOIL.
{{{(30-24i-5i+4i^2)/(25-20i+20i-16i^2)}}} Simplify. Replace: {{{i^2 = -1}}}
{{{(30-29i+4(-1))/(25-16(-1))}}}
{{{highlight((26-29i)/(41))}}}