Question 530607
the distance traveled by both is same when one catches up with the other.										
Let them meet at distance x										
Boy	speed=	20	mph		, starts at		11:00	am		
Another boy	speed=	35	mph		starts at		01:00	pm		
										
Time difference  between the starting of the two=			2.00	hours						
										
Time taken by  	Boy	=	X  /	20						
Time taken by  	Another boy	=	X  /	35						
										
X  /	20	-	X  /	35	=	2				
										
LCD -	140									
Multiply equation by 	140									
140/20	x-	140/35	x=	2	*	140
7	x  	-	4	x	=	280				
3	x  	=	280							
/	3									
x=   	93.33	miles								
Boy	speed=	20	mph							
Distance =  	93.33	miles								
Time taken =	93.33	/	20							
Time taken =	4.67	=								
0.67	hours	=	40.2	minutes						
They will be together at		03:37	pm