Question 530499
To get the range of the quadratic function, we first compute {{{(4ac-b^2)/4a}}}.
{{{(4ac-b^2)/4a = (4(1)(5)-(-7)^2)/4(1)}}}
                 ={{{-7.25}}}
The coefficient of {{{x^2}}} in {{{f(x)= x^2-7x+5}}}is positive therefore 
the range is {{{y >= -7.25}}}.