Question 530529
How do I reduce the fraction (4x+3)/(20x^2+23x+6) to simplest form, and include any restrictions on x?
-------------------------------
(4x+3)/(20x^2+23x+6)

---
Factor:
(4x+3)/[(4x+3)(5x+2)]
Restrictions on "x":
x cannot be -3/4; x cannot be -2/5.
----
Cancel the factor common to numerator and denominator to get:
= 1/(5x+2)
Cheers,
Stan H.
=========