Question 527699
Solve for X: 
log3(logx(Log16/Log4))=-1

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log3(logx(Log16/Log4))=-1
log3(logx(Log(2^4)/Log(2^2))=-1
log3(logx(4Log(2)/2Log(2))=-1
log3(logx(4/2)=-1
log3(log(2x)=-1
(log(2x)=-1/log3=-2.0959
2x=10^-2.0959=.008019
x=.004009