Question 530256
={{{(12w^4-6w^3+w^2)/3w^2}}}
={{{w^2(12w^2-6w+1)/3w^2}}}
={{{cross(w^2)(12w^2-6w+1)/3cross(w^2)}}}
={{{(12w^2-6w+1)/3)}}}
={{{12w^2/3-6w/3+1/3)}}}
={{{cross(12)w^2/cross(3)-cross(6)w/cross(3)+1/3)}}}
={{{4w^2-2w+1/3}}}