Question 530254
Let {{{ 1 }}} = unit of sulfuric acid solution originally
Let {{{ x }}} units of pure sulfuric acid to be added
given:
{{{ .45 }}} = units of sulfuric acid originally
---------
{{{ ( .45 + x ) / ( 1 + x ) = .8 }}}
{{{ .45 + x = .8*( 1 + x ) }}}
{{{ .45 + x = .8 + .8x }}}
{{{ .2x = .8 - .45 }}}
{{{ .2x = .35 }}}
{{{ x = 1.75 }}}
The ratio of pure acid to be added to solution already present 
must be 1.75/1 or 7/4